Indiana, with 10-2 victory, eliminates No. 21 Iowa from Big Ten tournament
MINNEAPOLIS -- All nine starters recorded a hit, Christian Morris gave up just two runs in six innings and Indiana is moving on in the Big Ten tournament with a 10-2 win against No. 21 Iowa.
The Hoosiers, who scored nine of their 10 runs in the second, third and fourth innings, will face No. 4 Maryland at 10 a.m. ET Saturday in their third consecutive elimination game.
Three swings of the bat resulted in eight runs in the aforementioned three-inning stretch and indirectly the ninth on an Iowa error.
Austin Cangelosi got things going in the second inning with a two-RBI triple, subsequently scoring on Iowa's throwing error that went into the IU dugout for a 3-0 lead.
Freshman outfielder Logan Sowers hit his second grand slam in the past four games, crushing a ball to left field at Target Field in the third to put Indiana ahead, 7-0.
Casey Rodrigue, who led IU with three hits, tripled to lead off that third inning before Brad Hartong walked and Scott Donley reached on catcher's interference to load the bases.
Rodrigue was again a catalyst in the fourth inning, tallying a double after Brian Wilhite's single to make way for Nick Ramos, who brought in both Hoosiers with a single, putting IU ahead 9-0.
Christian Morris earned the win, sitting Iowa down in order three times, shutting out the Hawkeyes through the first five frames.
Iowa did its only damage in the sixth, scoring two runs on a double to end Morris' day. But that was all Indiana would give up, adding another run of its own in the bottom of the stanza for good measure and a 10-2 lead.